Answer:
[tex]\large\boxed{f(2)=1;\ f^{-1}(1)=2;\ f^{-1}(f(2))=2}[/tex]
Step-by-step explanation:
We have:
[tex]f(x)=\dfrac{1}{2}x[/tex] and [tex]f^{-1}(x)=2x[/tex]
f(2) → put x = 2 to the equation of a function f(x):
[tex]f(2)=\dfrac{1}{2}(2)=1[/tex]
f⁻¹(1) → put x = 1 to the equation of a function f⁻¹(x):
[tex]f^{-1}(1)=2(1)=2[/tex]
f⁻¹(f(2)) → put f(2) = 2 to the equation of a function f⁻¹(x):
[tex]f^{-1}(f(2))=f^{-1}(1)=2[/tex]
