Answer:
Part a) The area of the tile is [tex]\frac{1}{9}\ ft^{2}[/tex]
Part b) The area of the tile is [tex]\frac{4}{9}\ ft^{2}[/tex]
Step-by-step explanation:
Part a) What is the area of the tile in square feet?
we know that
The area of a square is equal to
[tex]A=b^{2}[/tex]
where
b is the length side of the square
we have
[tex]b=\frac{1}{3}\ ft[/tex]
substitute the value
[tex]A=(\frac{1}{3})^{2}=\frac{1}{9}\ ft^{2}[/tex]
Part b) Isamu put 4 of the tiles together to make a square. Write and solve an equation to find the area, in square feet, of the square
we have that
The new length side of the tile is
[tex]b=2(\frac{1}{3})=\frac{2}{3}\ ft[/tex]
the new area is equal to
[tex]A=(\frac{2}{3})^{2}=\frac{4}{9}\ ft^{2}[/tex]
