Square ABCD is located on a coordinate plane. The coordinates for three of the vertices are listed below.
A (2,7) , C (8,1),D (2,1)
Square ABCD is dilated by a scale factor of 2 with the center of dilation at the origin, to form square A’B’C’D’. What are the coordinates if vertex B’?

Respuesta :

ANSWER

B' has coordinates (16,14).

EXPLANATION

The given coordinates of square ABCD are :

A (2,7) , C (8,1),D (2,1)

In order to form a square, the coordinates of B should be: (8,7)

The mapping for dilation with a scale factor 2, about the origin is

[tex](x,y)\to (2x,2y)[/tex]

This implies that:

[tex]B(8,7)\to B'(2 \times 8,2 \times 7)[/tex]

When we simplify we get:

[tex]B(8,7)\to B'(16,14)[/tex]

Hence B' has coordinates (16,14).