Respuesta :

ShyzaSling

Answer:

False

Step-by-step explanation:

Given in the question a function,

f(t)=1.2cos0.5t

Standard form of cosine function is

f(t)=acos(bt)

Amplitude is given by = |a|

Period of function is given by = 2π/b

So the amplitude is |1.2| = 1.2

    the period is 2π/0.5 = 4π

kudzordzifrancis

Answer:

False

Step-by-step explanation:

The given function is

[tex]f(t)=1.2\cos 0.5t[/tex]

This function is of the form:

[tex]f(t)=A\cos(Bt)[/tex]

where A=1.2 and B=0.5

The amplitude of this function is given by;

|A|=|1.2|=1.2

The period of this function is given by;

[tex]T=\frac{2\pi}{|B|}[/tex]

[tex]T=\frac{2\pi}{|0.5|}[/tex]

[tex]T=\frac{2\pi}{0.5}=4\pi[/tex]

The correct answer is False

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