Answer:
5)[tex]y=42000(1-0.08)^6[/tex]
6) 25467
Step-by-step explanation:
5) Use the formula;
[tex]y=y_0(1-r\%)^t[/tex]
where [tex]y_0=42000[/tex] dollars is the initial value of the car.
[tex]r\%=0.08[/tex]
and
t=6 years.
We plug in these values to obtain;
[tex]y=42000(1-0.08)^6[/tex]
Third choice is correct
6) The expected value of the car after 6 years is
[tex]y=254666.910[/tex]
We round to the nearest tenth to obtain;$ 25467
