Answer:
12560 J.
Explanation:
The amount of heat absorbed by water = Q = m.c.ΔT.
where, m is the mass of water (m = 1.5 kg = 1500.0 g).
c is the specific heat capacity of water = 4.186 J/g°C.
ΔT is the temperature difference = (final T - initial T = 27°C - 25°C = 2°C).
∴ The amount of heat absorbed by water = Q = m.c.ΔT = (1500.0 g)(4.186 J/g°C)(2°C) = 12560 J.