Answer: The answer is x^2 + y^2 + 6x - 8y + 21 = 0.
Step-by-step explanation:
First find the original standard form equation of the circle.
So the circle has a center of (-3, 4) and a radius of 2. Write this in standard form:
(x + 3)^2 + (y - 4)^2 = 2^2
Simplify:
(x + 3)^2 + (y - 4)^2 = 4
(x^2 + 6x + 9) + (y^2 - 8y + 16) = 4
Gather like terms:
x^2 + y^2 + 6x - 8y + 9 + 16 - 4 = 0
x^2 + y^2 + 6x - 8y + 21 = 0
There you go!
