Which equation has a graph that is a parabola with a vertex at (–2, 0)?
Answer is:
c. y=(x-2)^2

Question

contestada

Respuesta :

calculista calculista · Answer 1 · 2019-04-28T23:02:30+02:00

Answer:

The vertex of a quadratic equation corresponds to the point where the maximum or minimum value is located.

If the function has a positive leading coefficient, the vertex corresponds to the minimum value.

If it has a negative leading coefficient, the vertex corresponds to the maximum valuevalue

If the vertex is located at

(–2, 0)

The possibilities are

y = (x-2)^2

or,

y = - (x-2)^2

Since the problem tells us the answer, we adopt the positive values

Answer:

y = (x-2)^2

See attached picture

lisboa lisboa · Answer 2 · 2019-06-14T12:35:41+02:00

Answer:

[tex]y=(x+2)^2[/tex]

Step-by-step explanation:

A graph that is a parabola with a vertex at (–2, 0)

Vertex form of parabola equation is

[tex]y=a(x-h)^2 + k[/tex]

where (h,k) is the vertex

WE are given with vertex (-2,0)

(-2,0) is (h,k)

h=-2 and k=0

Plug the value in vertex form of equation. Lets take a=1

[tex]y=a(x-h)^2 + k[/tex]

Equation becomes [tex]y=1(x-(-2))^2 + 0[/tex]

[tex]y=(x+2)^2[/tex]