Write the equation of the line that includes the point (1,5) and has a slope of 3 in standard form.

Answer:
-3x + y = 2
Step-by-step explanation:
The slope is 3. So the coefficient of x is 3.
when x = 1, y = 5.
So 3*1 + c = 5
So c is 2.
So y = 3x + 2
Therefore, taking 3x to the LHS, we get,
-3x + y = 2
Hope it helps ;)
For this case we have that the equation of the point-slope form is given by:
[tex](y-y_ {0}) = m (x-x_ {0})[/tex]
Where:
m: It's the slope
[tex](x_ {0}, y_{0})[/tex]: It is a point through which the line passes
We have to:
[tex](x_ {0}, y_{0}) = (1,5)\\m = 3[/tex]
Then, the equation is:
[tex]y-5 = 3 (x-1)\\y-5 = 3x-3\\-5 + 3 = 3x-y\\-2 = 3x-y[/tex]
We multiply by "-" on both sides of the equation:
[tex]-3x + y = 2[/tex]
Answer:
Option B