hte area of a rectangle trampoline is 112 ft^2. the length of the trampoline is 6ft greater than the width of the trampoline, this situation can be represented by the equation w^2+6w-112=0
what is the lengeth of the trampoline in feet?
7
16
8
14

Respuesta :

Answer:

Step-by-step explanation:

alright, lets get started.

suppose the width is w.

the length is 6 feet greater than the width, so

length will be = w+6

area of the trampoline = length*width

[tex]area=(w+6)*w = w^2 +6w[/tex]

as per given, area is 112, so

[tex]w^2+6w=112[/tex]

subtracting 112 in both sides

[tex]w^2+6w-112=0[/tex]

factoring

[tex](w-8)(w+14)=0[/tex]

So, it will give two values of w

w=8 and w = -14

The width can't be negative, so

width = 8 feet.    :   answer

Hope it will help :)