Answer:
B. 2 x 10^2 m^3
Step-by-step explanation:
Given
Volume of submarine when full of water= 7.8 × 10³ m³
Total mass of submarine =8× 10⁶ kg
Density of sea water= 1000 kg/m³
Volume to be occupied by sea water at given mass of submarine=?
Apply; Density=mass/volume ⇒⇒volume=mass/density
where M=mas, V=volume, D=density
[tex]V=\frac{M}{D} \\\\\\\\V=\frac{8*10^6}{10^3} =8*10^3[/tex]
Excess volume= 8×10³ - 7.8× 10³ = 2×10² m³