For this case, we have that the figure shown is formed by a square and by two triangles (one on the top and one on the side of the square). By definition, the area of a triangle is given by:
[tex]A_ {t} = \frac {b * h} {2}[/tex]
Where:
b: It's the base
h: It's the height
On the other hand, the area of a square is given by;
[tex]A_ {s} = l ^ 2[/tex]
Where:
l: It's the side of the square.
The total area of the figure will be:
[tex]A_ {T} = A_ {t1} + A_ {t2} + A_ {s}\\A_ {T} = \frac {10 * 3} {2} + \frac {6 * 1} {2} + 6 ^ 2\\A_ {T} = 15 + 3 + 36\\A_ {T} = 54 \ units ^ 2[/tex]
Answer:
[tex]A_ {T} = 54 \ units ^ 2[/tex]
