Answer:
The surface area of the box increase by 0.2P (the perimeter of the base multiplied by 0.2)
Step-by-step explanation:
we know that
The surface area of the rectangular prism is equal to
[tex]SA=2B+Ph[/tex]
where
B is the area of the base
P is the perimeter of the base
h is the height of the prism
If the height is increased by 0.2
then
[tex]SA=2B+P(h+0.2)[/tex]
[tex]SA=2B+Ph+P(0.2)[/tex]
The surface area of the box increase by 0.2P (the perimeter of the base multiplied by 0.2)
