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The Japanese 5 yen coin has a hole in the middle. If the diameter of the coin is 22 mm and the diameter of the hole is 5 mm, how would you calculate in terms of how much longer the outer edge is than the inner edge?

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Animeaesthetic

Answer:

distance = (22/2) - (5/2) = 8.5 mm

Hope this helps chu

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facundo3141592

The difference between the circumferences is 53.4 millimeters.

How much longer the outer edge is than the inner edge?

Remember that for a circle of diameter D, the circumference is:

C = pi*D

where pi = 3.14159...

We know that the outer diameter of the coin is 22mm, then the outer circumference is:

C = 3.14*22mm = 69.1mm

The inner diameter is 5mm, then the inner circumference is:

C' = 3.14*5mm = 15.7mm

Then the difference is:

69.1mm -  15.7mm = 53.4mm

If you want to learn more about circles:

https://brainly.com/question/1559324

#SPJ2

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