Answer:
The area of the given triangle is 6.52 square feet.
Step-by-step explanation:
It is given that one side of the triangle is 3.8 ft and the opposite side is 4.3 ft. the angle connecting the two sides is 53 degrees.
Thus, Using the formula for the area of triangle, we get
[tex]{\text{Area of triangle}}=\frac{absinC}{2}[/tex]
Now, substituting the given values, we get
[tex]A=\frac{(3.8)(4.3)sin53^{\circ}}{2}[/tex]
⇒[tex]A=\frac{(16.34)(0.799)}{2}[/tex]
⇒[tex]A=\frac{13.05}{2}[/tex]
⇒[tex]A=6.52 ft^2[/tex]
Therefore, the area of the given triangle is 6.52 square feet.
