Respuesta :
Answer: 9/55
P(1st = red and 2nd = blue)
= (3/11) x (6/10)
= 18/110
= 9/55
To find the probability of something happening,
= (number of desired outcomes) / (total number of outcomes)
If you are finding the probability of more than one thing happening at the same time, you multiply the probability of both things happening together
P(1st = red and 2nd = blue)
= (3/11) x (6/10)
= 18/110
= 9/55
To find the probability of something happening,
= (number of desired outcomes) / (total number of outcomes)
If you are finding the probability of more than one thing happening at the same time, you multiply the probability of both things happening together
Answer:
[tex]\texttt{Probability that the first ball will be red and the second will be blue = }\frac{9}{55}[/tex]
Step-by-step explanation:
Total number of balls = 3 + 2 + 6 = 11
Probability is the ratio of number of favorable outcome to total number of outcomes.
[tex]\texttt{Probability that the first ball will be red = }\frac{\texttt{Total number of red balls}}{\texttt{Total number of balls}}\\\\\texttt{Probability that the first ball will be red = }\frac{3}{11}[/tex]
Now we have 10 balls in which 6 are blue.
[tex]\texttt{Probability that the second ball will be blue = }\frac{\texttt{Total number of blue balls}}{\texttt{Total number of balls}}\\\\\texttt{Probability that the first ball will be red = }\frac{6}{10}=\frac{3}{5}[/tex]
[tex]\texttt{Probability that the first ball will be red and the second will be blue = }\frac{3}{11}\times \frac{3}{5}\\\\\texttt{Probability that the first ball will be red and the second will be blue = }\frac{9}{55}[/tex]
