If B=16°45’ and c=13 then find a (picture provided)

Answer:
A. 12.4
Step-by-step explanation:
To find a, we'll use the Law of Sines that says:
[tex]\frac{a}{sin(A)} = \frac{c}{sin(C)}[/tex]
And we'll isolate a to get:
[tex]a = \frac{sin(A) * c}{sin(C)}[/tex]
We first need to find A, which is easy. The sum of the interior angles of a triangle is 180 degrees... and we already have 2 of them, so:
A = 180 - 90 - 16.75 = 73.25
(converted 16°45' to 16.75)
Then we will plug-in the information we already have
[tex]c = \frac{sin(73.25) * 13}{sin(90)} = 12.45[/tex]
So, let's round it to 12.4 to match the answer A.
Answer:
The length of side marked a is 12.4 units.
Step-by-step explanation:
In ΔABC
∠B = 16°45’ = 16.75°
1 min arc = [tex]\frac{1}{60} degrees [/tex]
c = 13 units
a = ?
[tex]\cos \theta=\frac{Base}{Hypotenuse}[/tex]
[tex]\cos B=\frac{a}{13}[/tex]
[tex]0.95757=\frac{a}{13}[/tex]
[tex]a=0.95757\times 13=12.4484\approx 12.4 units[/tex]
The length of side marked a is 12.4 units.