Answer:
= 97.44 Liters at S.T.P
Explanation:
The reaction between Iron (iii) oxide and Carbon monoxide is given by the equation;
Fe2O3(s)+ 3CO(g) → 3CO2(g) + 2Fe(s)
From the reaction when the reactants react, 2 moles of Fe and 3 moles of CO2 are produced.
Therefore; Mole ratio of Iron : Carbon dioxide is 2:3
Thus; Moles of Carbon dioxide = (2.9/2)×3
= 4.35 moles
But; 1 mole of CO2 at s.t.p occupies 22.4 liters
Therefore;
Mass of CO2 = 22.4 × 4.35 Moles
= 97.44 L
The volume of carbon dioxide produced is 97.44 L.
The equation of the reaction is;
Fe2O3 + 3CO --> 2Fe + 3CO2, we can see that the ratio of iron to carbon dioxide produced is 2:3.
From the reaction equation
3 moles of carbon dioxide is produced when 2 moles of iron is produced
x moles of carbon dioxide is produced when 2.9 moles of iron is produced
x = 3 moles × 2.9 moles/2 moles
x = 4.35 moles
If 1 moles of carbon dioxide occupies 22.4 L
4.35 moles of carbon dioxide occupies 4.35 moles × 22.4 L/ 1 moles = 97.44 L
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