Use the fact that [tex]\sin x = \sqrt{1-\cos^2 x}[/tex] to solve it.
[tex]\sin(\arccos(-\frac{9}{\sqrt{145}}))=\sqrt{1-\cos^2(\arccos(-\frac{9}{\sqrt{145}}))} =\\= \sqrt{1-(-\frac{9}{\sqrt{145}})^2}=\frac{8}{\sqrt{145}}[/tex]
Answer:
a
Step-by-step explanation:
