Answer:
H2O-a,e, C6H14 - b,c,d
Explanation:
H2O - (a) KI, e(NaC2H3O2) because they are ionic compounds
C6H14 -(b) C8H18 , (c) grease , (d) CH3(CH2)12OH because they are mostly un-polar.
The substances that would be soluble in H₂O are ; ( A and E )
The substances that would be soluble in C₆H₁₄ are ; ( B, C and D )
Substances that readily dissolves when placed in water are ionic compounds in nature and sodium acetate ( NaC₂H₃O₂ ) which is sodium salt will readily soluble when placed in water ( solvent ) also KI is an ionic compound hence it is soluble in water.
Un-polar compounds like C₈H₁₈ , grease and CH₃( CH₂ )12OH are not readily soluble in water but are readily soluble in Hexane ( C₆H₁₄ ).
Hence we can conclude that the substances that would be soluble in water are A and E while the substances that would be soluble in Hexane are B,C and D.
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