an elevator in a hotel moves at 20 feet per second. leaving form the ground floor, its height in feet after t second is given by the formula h(t)=20t. a bolt comes loose in the elevator shaft above, and its height in feet after falling for t second is given by h(t)=-16t^2+200. at what time and at what height does the bolt hit the elevator?

Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] Where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

As we know, the formula for the roots of the quadratic equation is given by:

[tex]\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]

When the bolt hit the elevator, they would be at the same height.

∴ 16t²+200 = 20t

16t² -20t + 200 = 0

It is a quadratic equation:

a = 16, b = -20, and c = 200 plug this values in the formula.

After calculating, we will get:

t = -4.2 or t = 3

Time cannot be negative.

So t = 3 seconds

And height h(3) = 20(3) = 60 feet

Thus, after 3 seconds and at 60 feet, the bolt hit the elevator if the height in feet after t second is given by the formula h(t)=20t.

Learn more about quadratic equations here:

brainly.com/question/2263981

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