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A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains 90% pure antifreeze. The company wants to obtain 180 gallons of a mixture that contains 70% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed?

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sqdancefan

Answer:

40 gallons of water and 140 gallons premium antifreeze

Step-by-step explanation:

Let p represent the number of gallons of premium antifreeze in the mix. Then 180-p is the number gallons of water. The amount of pure antifreeze in the mix is then ...

0.90p + 0·(180 -p) = 0.70·180

p = 0.70·180/0.90 = 140 . . . . divide by the coefficient of p

180-p = 40 . . . . . find the water content

40 gallons of water and 140 gallons of premium antifreeze are in the mix.

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