Answer:
0.10 m
Explanation:
The magnetic flux through the plane is given by
[tex]\Phi = BA[/tex]
where
B is the magnetic field intensity
A is the area of enclosed by the pipe
In this problem, we know
[tex]\Phi = 7.3\cdot 10^{-3} Wb[/tex] is the flux
B = 0.90 T is the magnetic field strength
Solving the equation for A, we find the area enclosed by the pipe
[tex]A=\frac{\Phi}{B}=\frac{7.3\cdot 10^{-3} Wb}{0.90 T}=8.1\cdot 10^{-3} m^2[/tex]
We know that the area is given by
[tex]A=\pi r^2[/tex]
where r is the radius. Solving for r, we find the radius:
[tex]r=\sqrt{\frac{A}{\pi}}=\sqrt{\frac{8.1\cdot 10^{-3} m^2}{\pi}}=0.05 m[/tex]
And so the diameter is twice the radius:
[tex]d=2r=2(0.05 m)=0.10 m[/tex]
