Answer:
77.98 g/mol ≅ 78.0 g/mol.
Explanation:
Molar mass of Al(OH)₃ = (Atomic mass of Al) + 3(Atomic mass of O) + 3(Atomic mass of H)
Atomic mass of Al = 26.98 g/mol. & Atomic mass of O = 16.0 g/mol & Atomic mass of H = 1.0 g/mol.
∴ Molar mass of Al(OH)₃ = (26.98 g/mol) + 3(16.0 g/mol) + 3(1.0 g/mol) = 77.98 g/mol ≅ 78.0 g/mol.