Answer:
a. the force between them quadruples
Explanation:
The electrostatic force between two charges is given by
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges
In this problem, the charges on both objects are doubled, so
[tex]q_1' = 2q_1\\q_2' = 2q_2[/tex]
While the distance does not change, so the new force will be
[tex]F'= k \frac{(2q_1)(2q_2)}{r^2}=4 (k\frac{q_1 q_2}{r^2})=4 F[/tex]
so, the force will quadruple.
