Answer:
[tex]\boxed{\text{C. 11.2 L}}[/tex]
Explanation:
The pressure is constant, so we can use Charles' Law to calculate the volume.
[tex]\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}[/tex]
Data:
V₁ = 22.4 L; T₁ = 273.15 K
V₂ = ?; T₂ = 136.58 K
Calculations:
[tex]\dfrac{ 22.4}{273.15} = \dfrac{ V_{2}}{136.58}\\\\0.082 00 = \dfrac{ V_{2}}{136.58}\\\\V_{2} =0.082 00 \times 136.58 = \boxed{\textbf{11.2 L}}[/tex]
