Answer:
V₂ = 14.56 mL.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n is constant, and have different values of P, V and T:
(P₁*V₁) / T₁ = (P₂ * V₂) / T₂
V₁ = 80.0 mL, P₁ = 0.20 atm, T₁ = 27 °C + 273 = 300 K.
V₂ = ??? mL, P₂ (STP) = 1.0 atm, T₂ (STP) = 0 °C + 273 = 273 K.
Applying in the above equation
(P ₁* V₁) / T₁ = (P₂ * V₂) / T₂
(0.20 atm * 80.0 mL) / 300 K= (1.0 atm * V₂) / 273 K
V₂ = (0.20 atm * 80.0 mL * 273 K) / (300 K * 1.0 atm)
V₂ = 14.56 mL
So, the answer is: V₂ = 14.56 mL.
