Answer:
Step-by-step explanation:
The formula of an area of a rectangle:
[tex]A=l\times w[/tex]
l - length
w - width
We have l = x + 12 and w = x - 5. Substitute:
[tex]A=(x+12)(x-5)[/tex] use FOIL (a + b)(c + d) = ac + ad + bc + bd
[tex]A=(x)(x)+(x)(-5)+(12)(x)+(12)(-5)[/tex]
[tex]A=x^2-5x+12x-60[/tex] combine like terms
[tex]A=x^2+7x-60[/tex]
[tex](2x-5)(3x^2-4x+2)[/tex] use the distributive property a(b + c) = ab + ac
[tex]=(2x-5)(3x^2)+(2x-5)(-4x)+(2x-5)(2)\\\\=(2x)(3x^2)+(-5)(3x^2)+(2x)(-4x)+(-5)(-4x)+(2x)(2)+(-5)(2)[/tex]
[tex]=6x^3-15x^2-8x^2+20x+4x-10[/tex] combine like terms
[tex]=6x^3+(-15x^2-8x^2)+(20x+4x)-10\\\\=6x^3-23x^2+24x-10[/tex]
