Respuesta :
Answer:
I believe it is 1/6 for the pencil and 1/3 for the pen. Altogether, 2/9.
Step-by-step explanation:
There is 1 purple pencil out of 6 and 1 black pen out of 3.
Using probability of independent events, it is found that there is a [tex]\frac{1}{15}[/tex] probability  that she will select a purple pencil and a black pen in that order.
A probability is the number of desired outcomes divided by the number of total outcomes.
If two events, A and B, are independent, the probability of both happening is the multiplication of the probabilities of each happening, that is:
[tex]P(A \cap B) = P(A)P(B)[/tex]
In this question:
- The pencil and the pen are independent.
- One of the five pencils are purple, thus [tex]P(A) = \frac{1}{5}[/tex].
- One of the three pens are black, thus [tex]P(B) = \frac{1}{3}[/tex].
The probability is:
[tex]P(A \cap B) = P(A)P(B) = \frac{1}{5} \times \frac{1}{3} = \frac{1}{15}[/tex]
[tex]\frac{1}{15}[/tex] probability  that she will select a purple pencil and a black pen in that order.
A similar problem is given at https://brainly.com/question/23855473