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A container is filled with hydrogen gas. It has a volume of 4 liters and a pressure of 2 atm. If the pressure of the container is increased to 6 atm without removing any of the gas or changing the temperature, what will the new volume be

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superman1987

Answer:

1.33 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

Knowing that:

V₁  =  4.0 L, P₁ = 2.0 atm,

V₂  =  ??? L, P₂ = 6.0 atm.

  • Applying in the above equation

(P ₁V₁) = (P₂V₂)

∴ V₂ = P ₁V₁/P₂ = (2.0 atm)(4.0 L)/(6.0 atm) = 1.33 L.

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