A Ray of light in air is incident on an air to glass boundary at an angle of 30. degrees with the normal. If the index of refraction of the glass is 1.52, what is the angle of the refracted ray within the glass with respect to the normal? A. 19 degrees B. 22 degrees C. 30 degrees D. 1.52

Respuesta :

Answer:

A

Explanation:

Snell's law states:

n₁ sin θ₁ = n₂ sin θ₂

where n is the index of refraction and θ is the angle of incidence (relative to the normal).

The index of refraction of air is approximately 1.  So:

1 sin 30° = 1.52 sin θ

θ ≈ 19°

The angle of refracted ray with respect to normal is 19°.

What is Snell's law?

It states that the ratio of sine of angle of incidence and angle of refraction is equal to the refractive index of second medium to the first medium.

sini/sinr =n₂/ n₁

Given the angle of incidence i = 30 degrees, refractive index of glass n₂=1.52, refractive index of air n₁ =1, then , angle of refraction is

1 x sin 30° = 1.52 x sin r

r ≈ 19°

Thus, the angle of refracted ray with respect to normal is 19°.

Learn more about Snell's law.

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