The perimeter of the original rectangle on the left is 30 meters. The perimeter of the reduced rectangle on the right is 24 meters. What is x, the width of the original rectangle on the left? Round to the nearest hundredth if necessary.

If the perimeter of the rectangle on the right is 24 m, and the length is 8, the width has to be 4, since 8+4+8+4=24. Since the scale factor is 24÷30=0.8 or 4/5, and the width of the rectangle on the right is 4, 4÷0.8=5, which is the width of the rectangle on the left.

Hope this helps! (P.S. I got it right on Edgenutiy, spelled wrong on purpose).

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indritachandra1999 indritachandra1999 · Answer 2 · 2022-06-18T06:12:51+02:00

The width of the original rectangle is 5m.

What is perimeter?

The perimeter of a shape can be described as the path or boundary that surrounds it .

Perimeter of Rectangle = 2 (L + B)

L = length of rectangle

B = breadth of rectangle

Perimeter of the reduced rectangle = 24m

Let the length of original rectangle be L1

Let the breadth of original rectangle be B1

Let L1 = 8m, B1 = 4m

P = 2( L1 + B1) = 2(8 + 4) = 24m

Scale factor = P(Original Rectangle) / P(reduced rectangle)

Scale factor = 30 / 24 = 1.25

So, width of original rectangle = Scale factor * reduced width

Width of original rectangle = 1.25 * 4 = 5m

Hence, the width of the original rectangle is 5m.

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