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. A hawk flying at a height of 60 feet spots a rabbit on the ground. If the hawk dives at a speed of 55 feet per second, how
long will it take the hawk to reach the rabbit?
(Hint: A model for the vertical motion of a projected object is given by the equation h = -16t2 + vt + s, where h is the height
in feet, t is the time in seconds, v is the initial velocity in feet per second, and s is the starting height of the object in feet. Use
this equation to find the time taken by the hawk to reach the rabbit.

Respuesta :

calculista

Answer:

The hawk reaches the rabbit at t=4.3 sec

Step-by-step explanation:

Let

h ----> is the height in feet

t ----> is the time in seconds

v ---> the initial velocity in feet pr second

s ----- is the starting height

we have

[tex]h=-16t^{2} +vt+s[/tex]

when the hawk reaches the rabbit the value of h is equal to zero

we have

[tex]v=55\ ft/sec[/tex]

[tex]s=60\ ft[/tex]

substitute

[tex]0=-16t^{2} +55t+60[/tex]

Solve the quadratic equation by graphing

The solution is t=4.3 sec

see the attached figure

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