Answer:
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}m+4n=8&(1)\\m=n-2&(2)\end{array}\right\\\\\text{substitute (2) to (1):}\\\\n-2+4n=8\qquad\text{add 2 to both sides}\\5n=10\qquad\text{divide both sides by 5}\\n=2\\\\\text{put the value of}\ n\ \text{to (2):}\\\\m=2-2\\m=0[/tex]