Respuesta :
Answer:
The  probability that the chosen animal feeds on seeds or insects or both is:
        [tex]\dfrac{3}{4}[/tex]
Step-by-step explanation:
Let A denote the event that the animal feed on seeds.
B denote the event that the animal feed on insects
and A∩B denote the event that the animal feed on both seed and insects.
and A∪B denote the event that the animal feeds on seeds or insects or both.
Let P denote the probability of an event.
Now, based on the information from the question we have:
[tex]P(A)=\dfrac{18}{36}\\\\P(B)=\dfrac{15}{36}\\\\P(A\bigcap B)=\dfrac{6}{36}[/tex]
Now, we know that:
[tex]P(A\bigcup B)=P(A)+P(B)-P(A\bigcap B)[/tex]
Hence, on putting the values we have:
[tex]P(A\bigcup B)=\dfrac{18}{36}+\dfrac{15}{36}-\dfrac{6}{36}\\\\\\P(A\bigcup B)=\dfrac{18+15-6}{36}\\\\\\P(A\bigcup B)=\dfrac{27}{36}=\dfrac{3}{4}[/tex]
