Hello!
The answer is:
The density is equal to:
[tex]78.6\frac{lb}{ft^{3} }[/tex]
Why?
This a unit conversion problem, so, converting the density of glycerin from [tex]gram/cm^{3}[/tex] to [tex]\frac{lb}{ft^{3}}[/tex] using the given conversion rates, we have:
[tex]1.26\frac{gram}{cm^{3}}*\frac{1lb}{454gram}*\frac{28317cm^{3} }{1ft^{3} }=78.59\frac{lb}{ft^{3} }[/tex]
Rounding to three significant figures, we have that the density is equal to:
[tex]78.6\frac{lb}{ft^{3} }[/tex]
Have a nice day!
