Answer: Last option.
Step-by-step explanation:
We need to apply the Rule for 90° counterclockwise rotation about the origin. Given a point [tex]P(x,y)[/tex]:
[tex]P(x,y)[/tex] → [tex]P'(-y,x)[/tex]
We can observe in the figure that the coordinates of the points E, F, G and H are:
[tex]E (2,6)[/tex]
[tex]F(7,-4)[/tex]
[tex]G(-2,-7)[/tex]
[tex]H (-5,1)[/tex]
Then, applying the rule, we get the coordinates of the new location of the figure EFGH:
[tex]E (2,6)[/tex] → [tex]E'(- 6,2)[/tex]
[tex]F(7,-4)[/tex] → [tex]F'(4,7)[/tex]
[tex]G(-2,-7)[/tex] → [tex]G'(7,-2)[/tex]
[tex]H (-5,1)[/tex] → [tex]H'(-1,-5)[/tex]
