Mr. And Mrs. Sears bought a house in 1962 for $60,000. The house was appraised in 2003, and was valued at $435,000.
a. What is the annual rate of increase in the value of the house?
b. If the house was originally built in 1950, what was it valued at then? (Assume the same
rate applied year after year.)

Respuesta :

1962 - 2003 = 41 years

In 2003 it’s value increased to = $435,000

$435,000 / 41 years

Per year’s value = $10,609.7561

B. 1950 - 1960 = 12 years

$60,000 / 12 years = $5000

Value of the house @ 1950 = $5000

Using proportions, it is found that:

  • a) The annual rate of increase in the value of the house was of 15.24%.
  • b) In 1950, the house was valued at $4,029.

Item a:

From an initial value of $60,000, the house increased in value by $375,000, as 435000 - 60000 = 375000.

The percent increase is given by:

[tex]\frac{375000}{60000} \times 100\% = 625\%[/tex]

In 2003 - 1962 = 41 years, hence:

[tex]r = \frac{625}{41} = 15.24[/tex]

The annual rate of increase in the value of the house was of 15.24%.

Item b:

The value increases 15.24% a year, hence, in t years after 1962, considering an initial value of $60,000, the value is:

[tex]V(t) = 60000(1.1524)^t[/tex]

1950 is 12 years before 1950, hence the value is V(-12), that is:

[tex]V(-12) = 60000(1.1524)^{-12} = \frac{60000}{(1.1524)^{12}} = 4029[/tex]

In 1950, the house was valued at $4,029.

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