Respuesta :
Answer:
One point: (2/3, 0)
Step-by-step explanation:
The fastest way to determine this is to find the discriminant, b^2-4ac:
discriminant = (-12)^2 - 4(9)(4) = 144 - 144 = 0
The rule here states that if the discriminant is 0, the function has two real, equal roots. Those roots are
-(-12) ± √0
x = ---------------- = 12/18, or 2/3.
2(9)
The graph touches the x-axis at x = 2/3, but does not cross it. In other words, the graph intersects the x-axis at only one x value: 2/3.
x = ------------------
The graph of the function y = 9x² - 12x + 4 intersect the x-axis at [tex]x = \frac{2}{3}[/tex] only.
What is x-intercepts ?
The x-intercepts are the points where the graph intersects the x-axis. The vertex is the point that defines the minimum or maximum of a parabola.
We have,
y = 9x² - 12x + 4
Now,
So, to get the x-intercept,
Put y = 0,
i.e.
0 = 9x² - 12x + 4
Now,
Using the mid term splitting method,
0 = 9x² - 12x + 4
0 = 9x² - 6x - 6x + 4
0 = 3x(3x - 2) -23(x - 2)
i.e.
0 = (3x - 2) (3x - 2)
Now,
3x - 2 = 0
⇒ [tex]x = \frac{2}{3}[/tex]
And,
Now,
3x - 2 = 0
⇒ [tex]x = \frac{2}{3}[/tex] ,
So,
The x -intercept is only at one point, i.e. [tex]x = \frac{2}{3}[/tex].
Hence, we can say that the graph of the function y = 9x² - 12x + 4 intersect the x-axis at [tex]x = \frac{2}{3}[/tex] only.
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