Answer:
The surface area of the rectangular pyramid is [tex]SA=109.50\ m^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of the rectangular prism is equal to the area of the rectangular base plus the area of the four triangular faces
so
[tex]SA=(8)(5)+2[14.75]+2[\frac{1}{2}(8)(5)][/tex]
[tex]SA=40+29.50+40[/tex]
[tex]SA=109.50\ m^{2}[/tex]
