The statement tan theta -12/5, csc theta -13/12, and the terminal point determined by theta is in quadrant 2."

Answer is C. This is because in quadrant 2, [tex]\sin\theta>0[/tex] so [tex]\csc\theta>0[/tex] is also true.
Answer with explanation:
Let , Theta =A
[tex]\tan A=\frac{-12}{5}\\\\ \csc A=\frac{-13}{12}[/tex]
In First Quadrant all Trigonometric Function are Positive.
→In Quadrant,II , Sine and Cosecant , Function are Positive only.
→Cosecant theta is negative.So, Terminal point can't be in Second Quadrant.
Option C: