Need help step by step. Thanks

Step-by-step explanation:
All of these are quadratic formula problems. Remember to properly use the quadratic formula, ax^2+bx+c=0.
For 3:
x^2+12x+36=49
x^2+12x-13=0
Using quadratic formula:
(-12+/-(12^2-4(1)(-13))^.5)÷2(1)
(-12+(196)^.5)/2=(-12+13)/2=1/2
=(-12-13)/2=-25/2
Answer:
3: x=1
4: x=8 AND -4
Step-by-step explanation:
3: x^2+12x+36=49
Subtract 36 from both sides
X^2+12x=13
X has to equal 1, because:
1^2+12=13
13=13
4:
x^2-4x-32=0
Multiply -32 by x^2
-32x^2
-4x
What number times another number equals -32?
What number plus another number equals -4?
-32x^2
-8x 4x
-4x
Complete the square
-8 -8x -32
x x^2 4x
x 4
(Factors are in bold)
then, x-8=0, x=8
AND
x+4=0
x=-4