Answer:
The weight of the enlarged paperweight is [tex]1.2\ lb[/tex]
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its volumes (or its weights) is equal to the scale factor elevated to the cube
Let
z-----> the scale factor
x ----> the enlarged paperweight weight
y ----> the original paperweight weight
[tex]z^{3}=\frac{x}{y}[/tex]
we have
[tex]z=2[/tex]
[tex]y=0.15\ lb[/tex]
substitute and solve for x
[tex]2^{3}=\frac{x}{0.15}[/tex]
[tex]x=2^{3}(0.15)=1.2\ lb[/tex]
