Answer: OPTION A
Step-by-step explanation:
You need to remember the logarithms properties:
[tex]log(a)+log(b)=log(ab)\\\\log(a)-log(b)=log(\frac{a}{b})\\\\log(a)^b=b*log(a)[/tex]
Rewrite the equation:
[tex]log(x(x-3))=log(3)+log(x)[/tex]
Like this logarithm has base 10, you can make this procedure:
[tex]log(x(x-3))-log(x)=log(3)[/tex]
[tex]log\frac{(x(x-3))}{(x)}=log(3)[/tex]
[tex]log(x-3)=log(3)[/tex]
[tex]10^{log((x-3))}=10^{log(3)}[/tex]
Then:
[tex](x-3)=3[/tex]
Now you need to solve for the variable "x":
[tex]x=3+3\\x=6[/tex]
