Respuesta :
Answer:
0.18 < t < 2.82.
Step-by-step explanation:
When h = 8 feet:
-16t^2 + 48t = 8
-16t^2 + 48t - 8 = 0
-2t^2 + 6t - 1 = 0
2t^2 - 6t + 1 = 0
Solving we get t = 0.18 and 2.82 seconds. At these times the stick is 8 feet off the ground.
Our inequality is 0.18 < t < 2.82.
Answer:
[tex]0.178<t<2.823[/tex]
Step-by-step explanation:
Given that Tim throws a stick straight up in the air from the ground.
The function
[tex]h = -16t^2 + 48t[/tex]
models the height, h, in feet, of the stick above the ground after t seconds
When height is more than 8 feet we have
[tex]h = -16t2 + 48t>8\\2t^2-6t+1>0\\[/tex]
Solution for this inequality would be
[tex]0.178<t<2.823[/tex]
