caerb
contestada

30 points to whoever can answer this please!

Complete the general form of the equation of a sinusoidal function having an amplitude of 6, a period of 2pi/3, and a phase shift to the left 1 unit.

Respuesta :

A common sinusoidal function is:

[tex]y = asin(bx)[/tex]

so,always amplitude is a, so a=6

and we know period is:

[tex]p = \frac{ |b| }{2\pi} [/tex]

so

[tex] \frac{ |b| }{2\pi} = \frac{2\pi}{3} [/tex]

[tex]b = + or - \frac{4 {\pi}^{2} }{3} [/tex]

and we have 2 equations that while we can consider which is appropriate ,to have its graph!

[tex]6 \sin( \frac{4 {\pi}^{2} }{3}x ) [/tex]
and when you want to shift it 1 unit left we have:
[tex]6 \sin( \frac{4 {\pi}^{2} }{3}x +1) [/tex]

Answer:

y=6sin3(x+1)

Step-by-step explanation: