Answer:
Part 1) The volume of each beam is [tex]1,858.88\ ft^{3}[/tex]
Part 2) You can fill [tex]26\ beams[/tex]
Part 3) Yes, the amount of sand left over is [tex]1,669.12\ ft^{3}[/tex]
Step-by-step explanation:
Part 1) What is the total volume of each beam?
The volume of a cylinder is equal to
[tex]V=\pi r^{2} h[/tex]
we have
[tex]h=37\ ft[/tex]
[tex]r=8/2=4\ ft[/tex] ----> the radius is half the diameter
assume
[tex]\pi=3.14[/tex]
substitute the values
[tex]V=(3.14)(4)^{2} (37)[/tex]
[tex]V=1,858.88\ ft^{3}[/tex]
Part 2) How many beams can you fill with this sand?
we know that
You are given a container with a 50,000 sq ft of sand for your beams
Note Is a 50,000 cubic foot of sand instead of 50,000 sq ft of sand
Divide the total volume of sand by the volume of each beam to obtain the number of beams
[tex]50,000/1,858.88=26.9\ beams[/tex]
Round down
[tex]26.9=26\ beams[/tex]
Part 3) Will you have any sand left over? If so how much?
yes
[tex]50,000-26(1,858.88)=1,669.12\ ft^{3}[/tex]