Respuesta :
Answer:
The number of positive three-digit even integers whose digits are among 9, 8, 7, 5, 3, and 1 are:
36
Step-by-step explanation:
We are asked to find the number of positive three-digit even integers whose digits are among 9, 8, 7, 5, 3, and 1.
We know that a number is even if the last digit of the number is divisible by 2 i.e. even.
Hence, the only digits among the given digits which is even is: 8
Now, at the first place any of the 6 digits could come up.
( Since, the digits could be repeated)
Also, at the second palace any of the 6 digits could come up.
Hence, the total number of such numbers possible are:
6×6×1=36
