Respuesta :

since it has a diameter of 4, then its radius is half that, or 2.

[tex]\bf \textit{lateral area of a cone}\\\\ LA=\pi r\sqrt{r^2+h^2}~~ \begin{cases} r=radius\\ h=height\\ \cline{1-1} r=2\\ h=10 \end{cases}\implies LA=\pi (2)\sqrt{2^2+10^2} \\\\\\ LA=2\pi \sqrt{104}\implies LA\approx 64.076[/tex]

luisejr77

Answer:[tex]A = 64.076\ units^2[/tex]

Step-by-step explanation:

The  lateral area of right cone is calculated by the following formula

[tex]A = \pi r *\sqrt{r^2 +h^2}[/tex]

Where r is the radius of the cone and h is the height

In this case we know that the diameter d of the base is:

[tex]d=2r[/tex]

So the radius is:

[tex]r=\frac{d}{2}\\\\r=\frac{4}{2}\\\\r=2\ units[/tex]

and

[tex]h=10\ units[/tex]

So the area is:

[tex]A = \pi*2 *\sqrt{2^2 +10^2}[/tex]

[tex]A = 64.076\ units^2[/tex]

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