Answer:
[tex]\frac{\sqrt{15} }{5} \\[/tex] and 16 is a solution to the original equation.
Step-by-step explanation:
To rationalize, you take
[tex]\frac{3 }\sqrt{15}[/tex] times [tex]\frac{\sqrt{15} }{\sqrt{15} }[/tex]
This will come out to be [tex]\frac{3\sqrt{15} }{15}[/tex] It then simplifies to [tex]\frac{\sqrt{15} }{5} \\[/tex].
To cancel out a square root, square both sides. You'll find w = 16
